S2_ 3 leg, normally open pushbutton switch L2_Toroidal core, Outside diameter of 33 mm, rounds in 19.8 mm, 11.1 mm thickness L1 is 5 turns of 17 AWG(1.2mm) L1_Toroidal core, Outside diameter of 46.7 mm, Rounds in 24.1 mm, 18 mm thickness L1 is 10 turns of 17 AWG (1.2mm) See the copper PCB layout and Component layout below. LED2 will show whether the current exceeds a preset. ![]() When detected load use current over than 9 Amperes, will cause voltage across R1 and R2 are more valuable (more than 0.45 volts)As a result, output of IC3 / 3 low, and to pull the reference voltage at pin 7 of IC3 / 2 to IC3 / 2 to produce the switching pulse with a lower duty cycle as a consequence, the output dropped to a value less than 2A.ĭuring the current over than the value set by the VR1, output of IC5 / 3 would be lower, according to the IC3 / 2 through D8, Make output IC4 / 4 higher. IC3 / 3 acts to reduce the output current. R40 are connected to the load to the circuit and when output voltage lower than 5volts The output of IC4/3 will high instead makes Q5 works and R41 will be to provide a load of circuit. When voltage ranges from 5V to 10V, the output of IC4/2 will be the compare circuit will has high current cause Q6 works. While the output voltage up to 10volts, R24 and R43 connected in parallel 2 pcs, Will act as a load to the circuit. ![]() Thus, you must have the load of the circuit. Normally, the switching power supply output is not constant. Capacitors C23 at pin 2 of IC5 / 1 are discharged, Until the output of IC5 / 1 high up, LED1 is lighted indicator non regulated. The output voltage of circuit will lower in unregulated form. The LED1 will no display, if Q1 get trigger gate at all times or Irregularities. And when output of IC4/1 lower the capacitor C23 at pin 2 of IC5/1 will higher up. When the negative pulse come in, output of IC4/1 will high, can through to charge C23 at pin 2 of IC5/1. Which is switching pulse and steady voltage at pin 7. That IC4 / 1 will compare voltage between pin 6. IC4 /1 and IC5/1 per share, to serve conditional no regulated. If momentary voltage exceeds 75V, it can trigger the effect of making it through Q1 D1 conduct another stroke should not be working. This voltage would drop all ZD3, No effect to the circuit. This means that, If the voltage does not exceed 75V. The limited voltage circuit while only 75 volts. Thus, so the D1 and ZD3 to prevent this voltage, which may cause the FET crash. The switching of Q1 in sometimes will cause the voltage brief moment at leg drain may be higher than the source. To the current sufficient to drive the gate of Q1 up. It drive the gate of Q1 that use as inverter in parallel to 5 pcs. Next IC2/1 will set the signal waveform, then send to IC2/2-IC2/6. It will detect the light as switching pulse signal then send to Q2 to Raise the signal. The pulse signal from the compare circuit will be sent to Q3 and Q4, Which is the buffer circuit to drive the LED in IC, that is the opto-isolator. But if the reference voltage has less switching pulse value so low duty cycle as Figure 3 ![]() IC3/2 will compare the voltage at both pins, if reference voltage has too much the output of IC3/2 will be a switching pulse (the square wave pulse) that has many duty cycle range. This reference voltage from output of IC5 / 4 will send to pin 7 of IC3/2, to compare with the signal at pin 6 of IC3/2 that connected from IC3/1, which is 20KHz frequency ramp generator circuit.įigure 2 the full circuit diagram of 0-45V 8A switching power supply IC5/4 is reference voltage booster circuit, which the output of IC5/4 will depending on adjusting VR3. Learn to Build: 0-50V 3A Adjustable Regulator Power supplyįigure 2 is complete circuit of this switching power supply. Which the duty cycle of this pulse switching will have high or low value depending on adjusting the output voltage that. The current flow through Q1 and L1 are too low,so the output is also low. During the Q1 performance, the current is passed through C8, C9, L1 and Q1, When Q1 stop or open circuit Energy stored in L1 will evolve through D2 and C8, C9 in the same direction, makes the output voltage is constant on all times.Īnd, if the pulse that send to control Q1, have the low duty cycle range. Figure 1 the basic of DC switching power supplyīoth Q1 and D2 will be passed to a high current, this will work alternately.
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